-8y^2=18y-5

Solution for -8y^2=18y-5 equation:

-8y^2=18y-5

We move all terms to the left:

-8y^2-(18y-5)=0

We get rid of parentheses

-8y^2-18y+5=0

a = -8; b = -18; c = +5;
Δ = b2-4ac
Δ = -182-4·(-8)·5
Δ = 484
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:
$y_{1}=\frac{-b-\sqrt{\Delta}}{2a}$
$y_{2}=\frac{-b+\sqrt{\Delta}}{2a}$

$\sqrt{\Delta}=\sqrt{484}=22$
$y_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(-18)-22}{2*-8}=\frac{-4}{-16}
=1/4
$
$y_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(-18)+22}{2*-8}=\frac{40}{-16}
=-2+1/2
$